P(2x-5)=x^2+x-2

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Solution for P(2x-5)=x^2+x-2 equation: 



(2P-5)=P^2+P-2

We move all terms to the left:

(2P-5)-(P^2+P-2)=0

We get rid of parentheses

-P^2+2P-P-5+2=0

We add all the numbers together, and all the variables

-1P^2+P-3=0

a = -1; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-1)·(-3)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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